AyurAstro · Geometry & Sound

The Sound of the Śrī Yantra

Chladni figures, a nine-triangle puzzle, and the exact recipe of drawing sacred geometry with vibration — an essay you can play with.

the classical concurrent figure · śakti ▽ sindoor · śiva △ verdigris
THE RECORDINGOne tone, twenty-seven strikes — the litany itself, 73 seconds
0:00 · 1:13

twenty-seven ticks, one per line of the figure — press play

THE RECORDING. The verdict of §6 taken literally. A single tone at 136.1 Hz — the Oṁ of the legend — struck twenty-seven times, once per line of the strict figure, in drawing order t₁ → t₉. Stereo bearing follows each edge's direction, loudness and ring time follow its full chord across the plate, and every line is positioned by starting phase alone. The bindu is a point, not a line; no wave can draw it, so the litany ends in silence. The script that renders this file sits below the references.

§ 1 · A legend written in sand

Can a sound draw this figure?

There is a story that travels wherever sound meets sacred geometry. Sing the syllable Oṁ into a tonoscope — a drum-like membrane dusted with fine powder — and the grains, the story says, arrange themselves into the Śrī Yantra: nine interlocking triangles around a central point, the great diagram of the Śrīvidyā tradition. The tale is usually traced back to the cymatics experiments of Hans Jenny in the 1960s, and you will find it repeated in books, documentaries, and a thousand yoga-studio posters.

This essay takes the legend seriously enough to do the physics. Not to knock it down with a shrug, but to ask the precise question hiding underneath: what would a vibration actually have to be, for sand to settle into the true, classical Śrī Yantra? The answer turns out to be exact, surprising, and — in its own way — more beautiful than the legend.

You need only three ideas from a good physics or math class: what a sine wave is, how vectors point, and the fact that waves add together. Everything else is built on this page. The green boxes suggest exactly what to type into each interactive figure, and every "show the work" panel folds open to reveal the math behind a claim. Nothing here is an image: every yantra is re-computed live in your browser.

§ 2 · Reading a plate

How sand reads a vibrating surface

In 1787 Ernst Chladni drew a violin bow across the edge of a metal plate sprinkled with sand, and watched the grains leap away from the moving parts and gather along still curves. The explanation is standing waves. Drive a plate at one of its natural frequencies and it settles into a mode: a pattern in which some regions swing up and down with full force while other points — the nodal lines — do not move at all. Sand gets kicked around by the vibrating regions until, by pure chance, it lands somewhere quiet, and there it stays. The sand pattern is literally a photograph of the equation ψ(x, y) = 0, where ψ is the plate's up-and-down motion at each point.

A square plate makes this concrete. Its simplest modes are products of cosines — one factor counting half-waves across the plate, the other counting them down:

ψ(x, y) = cos(mπx) cos(nπy) ± cos(nπx) cos(mπy)x and y run from 0 to 1 across the plate; m and n are whole numbers counting the half-waves

The ± matters. At many frequencies the plate has two different modes with the exact same pitch — the pattern (m, n) and its mirror twin (n, m) — and it is free to vibrate in any blend of the two. The famous curvy Chladni figures are exactly such blends.

Show the work — why pitch goes like m² + n²

A stiff plate's pitch grows with the square of how tightly the wave wiggles. The wiggle-rate across the plate is mπ, and down the plate it is nπ. Perpendicular wiggle-rates combine like the sides of a right triangle — Pythagoras — so the total squared wiggle-rate is k² = (mπ)² + (nπ)². Pitch is proportional to k², which is proportional to m² + n². So the (3, 5) figure hums at "34" while the (1, 2) figure hums at "5": the same plate, nearly seven times higher in this relative unit.

Try it — Plate I

Set m = 3, n = 5, combine −, sand ≈ 0.12: a classic Chladni figure. Now press combine +: same two modes, same pitch, completely different figure.

Now build a chord: at (3, 5) − press add this hum, then dial the sliders to (1, 2) +. Two tones, photographed one at a time and stacked — each stored hum keeps its own tint, and the live sliders always draw on top in pale sand. Click any chip to remove that hum; the stack holds six.

Then try m = 4, n = 4 with combine −. The two "twins" are now the same mode, and subtracting a thing from itself gives zero: the plate is still everywhere, so the whole plate floods with sand. That flood is the equation ψ ≡ 0 made visible.

PLATE IA square plate you can play
3 5 0.12

PLATE I. Sand (pale) collects where the plate is still. Raising m and n raises the pitch and multiplies the lines. Stack hums to layer exposures — a chord of the square plate, one photograph per tone; click a chip to unstrike it.

§ 3 · The control case

Why sound loves the Star of David

Now aim at triangles. A perfectly straight nodal line needs plane waves — waves whose crests are straight lines, all marching in one direction — and interlocking triangles need exactly three wave directions. So take three plane waves of the same wavelength, point them 120° apart, and give each a head start (a phase) of 2π/3:

ψ = sin(k e1·r + 2π/3) + sin(k e2·r + 2π/3) + sin(k e3·r + 2π/3)e₁, e₂, e₃ are unit vectors 120° apart; r = (x, y) is position; the pitch k sets the wavelength λ = 2π/k

Something almost magical happens: this sum of three waves factors into a product of three sine sheets. A product is zero wherever any factor is zero, and each factor is zero along a family of straight, evenly spaced, parallel lines. Three families at 60° to one another: the sand draws an endless lattice of interlocking up-and-down triangles. Hexagram country.

Show the work — the factor trick

Call the three arguments A, B, C. Adding them, the position r cancels because e₁ + e₂ + e₃ = 0 for three vectors 120° apart, leaving only the three head starts: A + B + C = 3·(2π/3) = 2π, a constant.

Now a classic identity. Sum-to-product gives sin A + sin B = 2 sin((A+B)/2) cos((A−B)/2). And since C = 2π − A − B, we get sin C = −sin(A+B) = −2 sin((A+B)/2) cos((A+B)/2). Add the two lines and factor out 2 sin((A+B)/2):

ψ = 2 sin((A+B)/2) [cos((A−B)/2) − cos((A+B)/2)] = 4 sin(A/2) sin(B/2) sin(C/2)

using cos u − cos v = 2 sin((v+u)/2) sin((v−u)/2) and sin((A+B)/2) = sin(π − C/2) = sin(C/2). Three factors, three families of straight nodal lines, spaced 2π/k apart. This factoring only works because the three head starts add to 2π — change the phases and the lines bend.

This lattice is the figure vibration draws effortlessly, and it is what cymatics rigs actually produce: Star-of-David tilings, honeycombs, and their cousins. To nest triangles of different sizes you need different wavelengths — a chord of pitches — because triangle size is proportional to wavelength, which is proportional to 1/frequency. And the tones must be struck one at a time, each pattern photographed and the photos stacked. Struck together, the three fields interfere, and sand can only rest at the rare spots where all three are quiet at once: dots, not lines.

Try it — Plate II

The poster-style nested yantra has triangle sizes about 1 : 0.7 : 0.49. Since size ∝ 1/pitch, set interval = 1.43 (because 1/0.7 ≈ 1.43), pitch = 8, and press chord, layered. On a stiff plate that chord is f, 1.43²f ≈ 2.04f, 1.43⁴f ≈ 4.17f — almost f, 2f, 4f: two octaves.

Now press chord, struck together at the same settings and watch the lines dissolve into dots. Then push interval = 3 layered: sizes 1 : ⅓ : ⅑.

PLATE IIThree waves at 120° — the equilateral trap
8.0 1.45 0.24

PLATE II. One tone gives the perfect interlocking-triangle lattice. Layering a chord nests three sizes — tinted here so you can see who drew what. Strike the chord all at once and superposition is unforgiving.

§ 4 · The strict figure

The Śrī Yantra as a system of equations

Everything Plate II can draw is equilateral, evenly spaced, and endlessly repeating. The Śrī Yantra refuses all three — and the refusal is precise, because the classical figure is not a freehand drawing but a system of constraints, studied in a small but serious mathematical literature from Bolton & Macleod in the 1970s through Kulaichev, Gérard Huet, and most recently Alessandro Chiodo's 2021 construction by straightedge and compass.

Here is the figure, stated as math. Nine triangles t₁ … t₉ share a vertical axis of symmetry, numbered by the height of their bases; t₁ through t₅ point down (the śakti triangles), t₆ through t₉ point up (the śiva triangles). Their interlocking must produce exactly 43 small triangles: the central trikoṇa holding the bindu, then rings of 8 (aṣṭakoṇa), 10 (antardaśāra), 10 (bahirdaśāra), and 14 (caturdaśāra). For those cells to close crisply, three families of rules must hold exactly:

(i) triangles t₃ and t₇ fit perfectly inside the same circle — apexes on its poles, base corners on its rim. (ii) Seven apexes must land exactly on other triangles' base lines: t₈'s apex on t₁'s base, t₆'s on t₂'s, t₉'s on t₃'s, t₁'s on t₆'s, t₅'s on t₇'s, t₄'s on t₈'s, and t₂'s on t₉'s. (iii) At twelve special points, three edges from three different triangles must pass through a single point — the triple concurrencies. The drawing tradition calls these points marma-sthāna — the same word Ayurveda uses for the body's vital junctions, where channels meet and injury cascades, and Vastu uses for the untouchable intersections of the vāstupuruṣamaṇḍala. The borrowing is exact: a marma is where the figure is most alive and most vulnerable, because an error at any one of the twelve spreads through the entire construction and breaks the cells.

Now count freedom. Nine triangles need 27 numbers to describe (each has a base height, a width, and an apex height). The rules above use up 23 of them. What is left is a family with just four free choices. The classical choice — Huet's — places the bases of t₃, t₆, t₇, t₉ at 0.332, 0.537, 0.602, 0.835 of the way down the vertical diameter. One last equation then remains, and it is equivalent to a problem Apollonius posed twenty-two centuries ago: find a circle tangent to a given circle and a given line, passing through a given point. That is why the strict yantra can be drawn with straightedge and compass — and why, on this page, your browser simply solves the last equation numerically every time you touch a slider.

Show the work — what exactly gets solved

After the four bases are chosen, the whole figure hangs on one unknown: the height xA of a helper point A on t₃'s base line. From A, every other line follows by chasing intersections — but the chain produces two independent predictions for where t₄'s base must sit: one from the rule that t₁'s and t₆'s legs meet on it, another from the rule that t₈'s leg passes through its corner. A valid yantra needs both predictions to agree. Your browser slides xA up and down (bisection — repeatedly halving the interval where the two predictions swap order) until they match to fifteen decimal places. For the classical bases the answer is xA ≈ 0.1256.

The solved classical figure · unit circle · y measured from centre
trianglepointsbase yhalf-widthapex yapex anglelegs
t₁+0.7740.520−0.07463.0°±58.5°
t₂+0.5380.649−0.67056.4°±61.8°
t₃+0.3360.942−1.00070.4°±54.8°
t₄+0.2080.325−0.47051.2°±64.4°
t₅+0.1030.228−0.20473.2°±53.4°
t₆−0.0740.320+0.53855.2°±62.4°
t₇−0.2040.979+1.00078.2°±50.9°
t₈−0.4700.714+0.77459.7°±60.1°
t₉−0.6700.466+0.33649.7°±65.2°

Three things in this table matter enormously for the physics. First, every apex angle is different — nine triangles, nine shapes, no repeats (t₈ lands, by pure accident, within a third of a degree of equilateral — highlighted above). Second, the nine base heights share no common measure: they are messy algebraic numbers full of nested square roots, and the traditional draughtsman's grid of 48 equal divisions was only ever an approximation to them. Third, the bindu — computed as the incentre of the central triangle — sits 0.042 R above the circle's centre. Concurrency alone does not centre the figure, which is why "optimal" versions in the modern literature add two more demands: a centred bindu and an exactly equilateral central triangle. (The appendix at the end of this page solves those.)

Try it — Plate III

Drag base t₃ → 0.360 and watch the whole organism re-derive itself — xA re-solves in the readout, and the pale marma dots refuse to split. Then push base t₆ → 0.575: the closure equation runs out of solutions, and the plate tells you so. reset to classical brings back Huet's figure.

PLATE IIIThe strict figure, solved as you watch
0.332 0.537 0.602 0.835

PLATE III. The four sliders are the figure's entire freedom. Everything else — five more triangles, eighteen legs, the bindu — is re-derived from the concurrency rules on every input.

§ 5 · Three prohibitions

What a nodal line is allowed to do

Now bring the solved figure to the plate. A vibration at a single frequency is a mix of plane waves that all share one wavelength; whatever directions and phases you choose, the resulting still-lines obey three hard rules. All three come from one idea: a straight nodal line acts as a mirror of odd symmetry — the plate's motion on one side is the upside-down mirror image of the other side — and symmetries, once present, spread.

Rule one: full chords only. If the plate is exactly still along a straight stretch, the mirror rule extends that stretch: it cannot simply stop at a point in the middle of the plate. Every straight nodal line runs boundary to boundary. But the yantra's edges must stop — every triangle side ends at a corner inside the plate. Whatever sound draws, it will draw each edge continued to the rim: the full chord, not the segment.

Show the work — why the line can't stop

Suppose the plate is still along a straight segment. Fold the plate along that line, in your imagination, with a minus sign: motion here equals minus the motion at the mirror point. Along the fold both sides must agree, and the only number equal to its own negative is zero — consistent so far. But the mirror rule is a statement about the whole wave equation, not about your segment: once the motion is odd across part of the line, the equation forces it to stay odd across the line's entire continuation. The mirror does not know where you wanted the segment to end.

Rule two: parallels live on one ladder. Look across a family of parallel still-lines, perpendicular to them. Each wave component contributes a plain sine along that direction, and a sine crosses zero at perfectly equal steps. So within one tone, parallel nodal lines must sit on a single ladder of equal spacing — and every rung of the ladder prints, wanted or not. Lines at unrelated spacings cannot share a tone.

Show the work — the equal-steps rule

Call the direction across the lines v. A single-frequency field, sorted by how fast it wiggles along the lines, breaks into groups, and each group's dependence on v is one sinusoid: a sin(kvv) + b cos(kvv). A sinusoid's zeros are evenly spaced, exactly π/kv apart. If you need it to vanish at two chosen positions p₁ and p₂, the gap must be a whole number of steps:

kv (p₂ − p₁) = mπ, m a whole number

— and then the sinusoid also vanishes at every other step. That is the ladder, rungs included.

Rule three: crossings at 90°, or the equilateral trio. Two crossing nodal lines are two mirrors, and two mirrors meeting at an angle generate a rotation of twice that angle. Unless the angle divides 180° evenly, the copies never stop multiplying and the only field that can obey them all is zero everywhere. If the angle does divide evenly, the whole family of mirror copies prints — ghost spokes radiating through the crossing. Exactly two clean escapes exist: perpendicular crossings, where the field factors as sin(ax) sin(by) with the two spacings free; and the 120° trio of § 3, where the factorization forces equilateral triangles with all spacings equal.

RULE 1 — the edge you want (solid) is completed to its full chord (dashed). No straight node may end inside the plate.
RULE 2 — one tone holds parallels only on a single ladder of spacing s, and every rung prints — including the one you did not ask for.
RULE 3 — a 60° crossing drags the third mirror of the trio with it (dashed); any other angle except 90° forbids the crossing outright.

Now hold the yantra's census against the rules. Its nine base heights share no common measure — rule two forbids them from sharing a tone. Its eighteen leg directions are all different, none at 90° to any other line of the figure, and no three of its directions form the equilateral trio — rule three forbids any two crossing edges from sharing a tone. Even the two legs of one triangle, mirror twins though they are, meet at an apex angle that is not a neat divisor of 180°, so pairing them under one tone would spray ghost spokes through the apex. The strict figure breaks all three prohibitions everywhere, at once. One tone — indeed any chord of tones on a uniform plate — cannot draw it.

§ 6 · The bill

One tone, twenty-seven bearings

Impossibility, made precise, becomes a price list. If no two edges may share a tone, give each edge its own exposure, just as the nested hexagrams demanded in § 3 — only now the trick runs in a different dimension. The recipe for one straight line is a pair of plane waves skimming along it at shallow angles ±β, phased so that their combined stillness lands exactly on the target. The pair's still-lines repeat, so choosing β small enough,

sin β < λ / 2Lλ = wavelength, L = width of the plate — the condition that pushes every ghost parallel off the plate

leaves exactly one line on the plate: the full chord through the target edge, positioned not by frequency but by phase.

Show the work — where λ/2L comes from

Two waves at angles ±β to a line combine into stripes parallel to it. Across the stripes the effective wavelength stretches to λ/sin β (skim shallower, stretch longer), and still-lines occur every half of that: λ/(2 sin β) apart. Demand that this spacing exceed the plate's width L, so the neighbours fall off the edge, and rearrange: sin β < λ/2L.

That prices the figure precisely:

What each family of edges demands
familylinesdirectionscan they share a tone?exposureswaves
horizontal bases91no — spacings incommensurate918
triangle legs1818no — no 90° pairs, no 60° trio1836
the strict yantra, edge by edge27192754
sharpened minimum2719three base pairs share ladders2448

The last row is a refinement worth showing. Two parallel lines can share one ladder — if both of the ladder's next rungs fall off the plate. On a plate of radius 1, that means the pair (y₁, y₂) must satisfy 2y₁−y₂ ≤ −1 and 2y₂−y₁ ≥ +1, and exactly three pairs of the yantra's bases qualify, each joining a deep śiva-side line to a high śakti-side one: {−0.670, +0.208}, {−0.470, +0.336}, {−0.204, +0.774}. The true minimum is therefore twenty-four exposures and forty-eight waves; twenty-seven is the honest edge-by-edge prescription.

Show the work — checking one pair

Take the pair y₁ = −0.204 and y₂ = +0.774. The ladder step is Δ = y₂ − y₁ = 0.978. The next rung below sits at y₁ − Δ = 2y₁ − y₂ = −1.182, and the next above at y₂ + Δ = 2y₂ − y₁ = +1.752. The plate only reaches from −1 to +1, so both ghost rungs miss it entirely: two target lines, one tone, no ghosts. Try the same test on the neighbours y = −0.074 and +0.103: Δ = 0.177, next rungs at −0.251 and +0.280 — both squarely on the plate. Ghosts. That pair must stay separate.

Forty-eight waves at the optimum, fifty-four in the full prescription — and here is the inversion that makes the strict yantra the mirror image of its stylized cousin. The nested hexagrams differed by size, so they were spread across frequencies: one direction set, a chord of pitches. The strict yantra's edges differ by direction and position — quantities carried by bearing and phase — so every exposure can use the same single frequency. Not a chord at all: one note, struck again and again from different compass bearings around the rim, the sand photographed between strikes and the photographs stacked.

Show the work — why "all at once" fails

Be clear about the counting first: one exposure is one pair of waves, so twenty-seven strikes use 27 × 2 = 54 waves in total — two at a time. The all-at-once mode uses the very same 54 waves; the only change is simultaneity.

During strike #7, only pair #7 is sounding. Its silence along edge #7 is a true silence, and sand collects there. Sound every pair together and the field on edge #7 becomes zero-from-pair-7 plus the motion of the other twenty-six pairs — which is not zero. Waves add as vibrations, not as photographs: there is no way to add twenty-seven pictures without also adding their motions. Your browser fits the best possible amplitudes and phases for the blend, and the figure still floods. That flooding is Plate II's "struck together" lesson, paid at full scale — and it is why the prescription must be sequential.

Try it — Plate IV

The solution, at its cleanest: in one pair at a time mode, drop sand = 0.05. There it is — the strict Śrī Yantra in thin bright lines, every angle exact, every edge running rim to rim (rule one, obeyed). In this mode the pitch slider is idle and dims to say so: each line's position is carried by bearing and phase, not wavelength.

Then switch to the same 27 pairs, all at once — identical waves, now simultaneous. Pitch matters here (it sets the blend's wavelength): try pitch = 50, and watch each pair's silence flood with the motion of the other twenty-six, no matter how the browser balances them.

PLATE IVThe strict yantra, paid for in waves
24 0.16

PLATE IV. Here we finally see the Shri Yanra: set pitch to 50, sand to 0.05, and choose 27 strikes (as in a gong strike). Left mode: the honest stack — every exposure at one frequency, each contributing one full chord. Right mode: the very same 54 waves sounded together instead of in sequence — each pair’s silence floods with the other pairs’ motion, however cleverly the browser balances them. The sindoor overlay is the figure the tradition actually draws.

§ 7 · Residues

What the sand finally says

Even the honest stack keeps residues worth staring at. First, every edge prints as its full chord — rule one is not negotiable — so what vibration renders is a wave-completed yantra: the classical figure plus the continuation of each of its twenty-seven edges, the threads of the loom left visible. Second, a nodal line has no width but a sand line does: its thickness is set by how quiet counts as quiet. And third — flip Plate IV to its all-at-once mode — the same fifty-four waves sounded together surrender most of the figure, because each pair’s silence fills with the others’ motion. The sequential strikes were never a convenience. They are what superposition demands.

So the legend receives a precise verdict. No syllable — no sound of any kind — sung over a uniform plate or membrane deposits sand into the strict Śrī Yantra; the incommensurate heights, the nineteen unrepeated directions, and the interior corners each forbid it on their own. What the tonoscope can produce, and what the cymatics films do show, is the equilateral lattice of § 3 — geometry's echo of the yantra, not the yantra. Engineered instruments can do better: plates cut to the figure's outline, thickness graded to bend nodal lines, or arrays of dozens of speakers doing acoustic holography can approach the strict figure to within a wavelength. But each of these is a way of building the answer into the instrument — which is, perhaps, the point.

Because the tradition never claimed the yantra was a recording. In the Śrīvidyā literature the figure is a vidhi — a prescription, a thing to be constructed, stroke by stroke, in copper or in the mind's eye, with the marma junctions closing exactly. The physics returns the compliment with unexpected grace: asked what it would take to sound the figure into being, the answer is itself a prescription of ritual clarity — one tone, struck twenty-seven times, from twenty-seven bearings, each strike placing one line by phase alone. Not a chord but a litany. The legend, read carefully, was never about what sand does on its own. It was about how much order you must already possess before the sand will agree with you.

Every claim above, on a single plate, as a coda. Choose what the plate hears — one uniform hum, a chord of three struck one at a time or together, or the full prescription — and lay the figures over the sand: the strict Śrī Yantra, the stylized nested-hexagram yantra of the posters, the Star of David.

Try it — Plate V

Turn on the Star of David overlay in one uniform hum mode. Set pitch = 4.93: the star's upward triangle locks onto the sand exactly. Now pitch = 9.86: its downward twin locks — and the upward one lets go. No pitch locks both.

Then three hums, layered with interval = 1.43 against the stylized nested yantra overlay; and finally one tone × 27 bearings against the strict Śrī Yantra.

Show the work — the lock pitches

One tone's nodal lines are spaced d = 2π/k apart, so the smallest upward sand-triangle at the plate's centre has height d — and an equilateral triangle's centre sits one third of the way up, so its tip reaches R = ⅔·d = 4π/(3k) from centre. Setting R equal to the overlay's 0.85 gives k = 4π/(3 × 0.85) ≈ 4.93.

The lattice also owns a downward triangle concentric with that centre — but only at exactly twice the size, R = 8π/(3k). Setting that to 0.85 gives k ≈ 9.86. Locking both equal triangles at once would need 4π/3k = 8π/3k, which no k satisfies. A single hum holds concentric opposed triangles only at sizes 1 : 2 — so even the Star of David, strictly drawn as two equal triangles, exceeds one tone. Verified on this page to fifteen decimal places.

PLATE VOne hum, three hums, or the full prescription — against every figure
8.00 1.45 0.22

PLATE V. The comparator. A single hum tiles the plate with the star's motif and locks onto the Star overlay one triangle at a time — never both, a small theorem in itself; three hums layered fit the stylized nested yantra at interval ≈ 1.43; nothing the plate hears — at any pitch, in any chord — fits the strict figure except the twenty-seven-fold prescription of one tone.

Appendix · The optimal family

When the bindu must sit at the centre

Section 4 left the classical figure with two blemishes: a bindu riding 0.042 R above centre, and a central triangle of 63.0° rather than a clean 60°. The modern literature's "optimal" yantra demands both fixed — a centred bindu and an equilateral central trikoṇa. Those are two equations, and the figure has four free choices, so a two-parameter family of optimal yantras survives. Plate VI solves, live, the one nearest to Huet's classical figure — and then goes further, spending the remaining freedom on purpose: pinning t₈, and finally t₂, to 60° as well, ending in a figure with no freedom left at all. Gold marks the exactly equilateral triangles.

How the census shifts across the family
variantconstraints spentdirectionsmin. exposureswavesbindu
classical (Huet)0 of 4192448+0.042 R
concentric + t₁ = 60°2 of 41924480
+ t₈ = 60°3 of 41724480
+ t₂ = 60° (determined)4 of 41524480

Two findings, one on each side of the ledger. The direction count can be pushed from nineteen down to fifteen — but only deliberately; the two optimality conditions by themselves move nothing, and even push t₈ away from the 60° it grazed by accident. The wave bill refuses to move at all: twenty-four exposures, forty-eight waves, across the whole family. Merged directions do create parallel legs, but they huddle within 0.37 R of the axis, and by rule two a shared tone would print ghost rungs right on the plate. Parallelism only pays across the plate's full breadth, and the only parallels that far apart are the three base pairs already counted.

The last variant carries a small theorem of its own. With every degree of freedom spent, t₂ and t₈ become exact equilateral triangles pointing opposite ways — a Star of David in the making — yet their sides differ by 6.7%, and nothing is left to close the gap. The hexagram of the cymatics films is not just a different figure from the Śrī Yantra; it lies provably outside the yantra's constraint system. Sound's favourite figure and the tradition's figure cannot be deformed into one another without breaking a marma.

Try it — Plate VI

Step through the four buttons with classical underlay on. Watch the bindu jump to the exact centre on the second button, the gold spread on the third and fourth — and the readout: directions fall 19 → 17 → 15 while the exposures never budge from 24.

PLATE VIFour ways to spend four degrees of freedom

PLATE VI. Every variant is re-solved in your browser by Gauss–Newton iteration over the four free parameters, with the closure equation bisected inside each step. The small cross marks the circle's centre.